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7 part 1
7.
{|! p || q || r || p.q⊃r || p∨q⊃r || p⊃(aq⊃r)|| q⊃(p⊃r) || (p⊃r).(q⊃r) || (p⊃r)∨(q⊃r)|-|T || T || T  || T      || T      || T       || T         || T            || T|-|T || T || F  || F      || F      || F       || F         || F            || F|-|T || F || T  || T      || T      || T       || T         || T            || T|-|T || F || F  || T      || F      || T       || T         || F            || T|-|F || T || T  || T      || T      || T       || T         || T            || T|-|F || T || F  || T      || F      || T       || T         || F            || T|-|F || F || T  || T      || T      || T       || T         || T            || T|-|F || F || F  || T      || T      || T       || T         || T            || T|}Thus we can see that #1, 2, and 4 are equivalent to p.q⊃r while #3 is equivalent to p∨q⊃r
8.